Free art contest!
11 years ago
General
If you can answer the following problem you will get a completly free picture drawn by me, no strings attached, any content, any theme, any character (but maximum of two characters)
A man has 12 coins, one of which is forged, the only thing we know about the forged coin is that it weighs either more or less then the real ones. He has a balance scale at his disposal to weigh them (but he has no weights other than the coins to use)
How can the man, with a maximum of 3 weight measurements determine which coin is forged and if it weighs more or less than the real ones.
Answer me this problem and you will be rewarded with art.
A man has 12 coins, one of which is forged, the only thing we know about the forged coin is that it weighs either more or less then the real ones. He has a balance scale at his disposal to weigh them (but he has no weights other than the coins to use)
How can the man, with a maximum of 3 weight measurements determine which coin is forged and if it weighs more or less than the real ones.
Answer me this problem and you will be rewarded with art.
FA+

Weight any 4 with any other 4.
Case 1. This first weighing (4 with 4) balances.
Then the 8 coins that you weighed are all good and the 4 that you didn't weigh are suspects for the fake coin.
Weigh 3 good coins against 3 suspect coins.
A. If they balance then the remaining suspect coin is the fake coin, so then you weigh the fake coin with one of the good coins to see whether its heavier or lighter.
B. If they don't balance then you can tell whether the suspect coin is heavier or lighter, so weigh one suspect coin with another. If they weigh the same, the remaining one is the fake one, and if they don't, you know which of the two on the scale is the fake one because you already know whether it's heavier or lighter.
Case 2. The first weighing 4 with 4 doesn't balance. Then put two from the heavier side and one from the lighter side on each side of the scale.
A. If they balance then you know the fake coin is one of the two from the previous lighter side that you didn't weigh, and you also know that the fake coin is lighter. So weigh one of those with a good coin. If those balance then you know the one you didn't weigh is the fake coin and you know it's lighter. If they don't balance, then the lighter one on the scale is the fake one.
B. If they don't balance, then the fake coin is either one of the ones on the PRESENT heavy side from the PREVIOUS heavy side and it's heavier, or you know that the fake coin is one from the PRESENT lighter side from the PREVIOUS lighter side and it's lighter. Now from the PRESENT heavy side, weigh one from the PREVIOUS heavy side with the other from the PREVIOUS heavy side. If they weigh the same, then the fake coin is the one from the PREVIOUS lighter side and it's lighter. Otherwise the heavier one from the PREVIOUS heavier side is the fake coin and it's heavier.
Umm.. I will poke you tomorrow perhaps (I'm just about to go to sleep ;) )
Should not answer to mathproblems when waking up or going to sleep :)
After you have determined 2 real coins, continue to weigh each remaining coin against a real one until one coin is either lighter, or heavier than the other. You have found the fake coin, and weather it was heavier or lighter.
If the first two coins you have selected do not balance, set them aside and try two other coins, they should balance. Then try each of those first two coins, witchever does not balance is the fake coin. You have found the fake coin, and weather it was heavier or lighter.
i did not read the 'maximum of three' weight limit. WELL. i'm dumb, and the guy above me probably won. :D