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My Organic Chem II professor is so incredibly boring the only way to survive his lectures is to spend the class doodling the fantasy teacher I only wish I could have.
Category Artwork (Digital) / Fantasy
Species Hyena
Size 798 x 600px
File Size 176.9 kB
Listed in Folders
I can sympathize. My first calc TA had an accent so thick that the only thing we could understand was 'so clearly...'
That said, the closest thing I had to this professor was in the Gender Studies department. I recommend it for your electives if you have one. Very ... interesting place.
That said, the closest thing I had to this professor was in the Gender Studies department. I recommend it for your electives if you have one. Very ... interesting place.
I know what that's like.
This helped me.
https://www.khanacademy.org/science.....anic-chemistry
http://www.masterorganicchemistry.com/
This helped me.
https://www.khanacademy.org/science.....anic-chemistry
http://www.masterorganicchemistry.com/
this reminds vaguely of my O-Chem teacher in college
*scribbles reactions on the chalk board*
*lectures for a while*
*actually looks at what he's put up on the chalkboard*
oh ... whoops, that's how you freebase coke
*hastily erases*
... plus he had the theme for the Boondocks cartoon show as the ringtone for his cell phone
*scribbles reactions on the chalk board*
*lectures for a while*
*actually looks at what he's put up on the chalkboard*
oh ... whoops, that's how you freebase coke
*hastily erases*
... plus he had the theme for the Boondocks cartoon show as the ringtone for his cell phone
Hmm... That benzene ring seems to have a methyl substituent already on it, which would make it methylbenzene.
Now of course, you can still bromonate methylbenzene, but the bromine will not attack the methyl group, and instead will instead electrophillically substitute one of the remaining hydrogen atoms on the ring.
Since the methyl group is an ortho, para director, the major products of such a reaction would place the bromine on the 2 or 4 position relative to the methyl group, with only a minor fraction of the product being in a meta (3 position) configuration.
Furthermore, as bromine is a deactivating group, it's presence on the aromatic ring will reduce the rate of further electrophilic reactions on the ring, however it is still possible to substitute all the remaining hydrogens on the ring with enough time.
Theoretically, you could also use a reverse Friedel-Crafts reaction to remove the methyl group, but as far as I am aware, weird shit happens when you try that which is why it's just a theory.
This concludes my complete overanalysis of internet science smut for the day!
Now of course, you can still bromonate methylbenzene, but the bromine will not attack the methyl group, and instead will instead electrophillically substitute one of the remaining hydrogen atoms on the ring.
Since the methyl group is an ortho, para director, the major products of such a reaction would place the bromine on the 2 or 4 position relative to the methyl group, with only a minor fraction of the product being in a meta (3 position) configuration.
Furthermore, as bromine is a deactivating group, it's presence on the aromatic ring will reduce the rate of further electrophilic reactions on the ring, however it is still possible to substitute all the remaining hydrogens on the ring with enough time.
Theoretically, you could also use a reverse Friedel-Crafts reaction to remove the methyl group, but as far as I am aware, weird shit happens when you try that which is why it's just a theory.
This concludes my complete overanalysis of internet science smut for the day!
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