You probably this I'm just going to giggle and move on from this, but no. I'm going to seriously answer this question, ready?
First we need to collect the verbals for this equation.
1) the energy (in calories) that the average weiner contains
2)the conversion of calories to Joules
3)the energy consumption of the ISS for both a day and 2 1/2 days in joules
With that in mind
●The average hotdog is 110 calories
●there are 4.184 joules per calorie so its 460.24 for 110 calories
●the ISS uses 90 kilowatts per day (225 kilowatts for 2 1/2 days)
●1 kilowatt is equal to 3600000 joules so 90 kilowatts would be equal to You probably this I'm just going to giggle and move on from this, but no. I'm going to seriously answer this question, ready?
First we need to collect the verbals for this equation.
1) the energy (in calories) that the average weiner contains
2)the conversion of calories to Joules
3)the energy consumption of the ISS for both a day and 2 1/2 days in joules
With that in mind
●The average hotdog is 110 calories
●there are 4.184 joules per calorie so its 460.24 for 110 calories
●the ISS uses 90 kilowatts per day (225 kilowatts for 2 1/2 days)
●1 kilowatt is equal to joules so 90 kilowatts would be equal to 324000000 joules (810000000 joules for 225 kilowatts)
With these variables we can come to the conclusion that
●324000000 joules (1 day) is equal to 77437858.5086 calories
193594646.272 calories for 2 1/2 days
Time for the moment of truth...
It would take 703,980.53189636 wieners to power the ISS for 1 day
Or
1,759,951.3297454 wieners to power the ISS FOR 2 1/2 days
Well thanks, unfortunately I don't have time to fix my equation. If you are interested in the correct answer I encourage you to try solving it yourself *flops*
You wake up and start getting ready for the day when you see a naked gator dad with a come hither stare, naked on your bed, beckoning you to join him. Do you call in sick and hop on pop or just go about your day? :3c
First we need to collect the verbals for this equation.
1) the energy (in calories) that the average weiner contains
2)the conversion of calories to Joules
3)the energy consumption of the ISS for both a day and 2 1/2 days in joules
With that in mind
●The average hotdog is 110 calories
●there are 4.184 joules per calorie so its 460.24 for 110 calories
●the ISS uses 90 kilowatts per day (225 kilowatts for 2 1/2 days)
●1 kilowatt is equal to 3600000 joules so 90 kilowatts would be equal to You probably this I'm just going to giggle and move on from this, but no. I'm going to seriously answer this question, ready?
First we need to collect the verbals for this equation.
1) the energy (in calories) that the average weiner contains
2)the conversion of calories to Joules
3)the energy consumption of the ISS for both a day and 2 1/2 days in joules
With that in mind
●The average hotdog is 110 calories
●there are 4.184 joules per calorie so its 460.24 for 110 calories
●the ISS uses 90 kilowatts per day (225 kilowatts for 2 1/2 days)
●1 kilowatt is equal to joules so 90 kilowatts would be equal to 324000000 joules (810000000 joules for 225 kilowatts)
With these variables we can come to the conclusion that
●324000000 joules (1 day) is equal to 77437858.5086 calories
193594646.272 calories for 2 1/2 days
Time for the moment of truth...
It would take 703,980.53189636 wieners to power the ISS for 1 day
Or
1,759,951.3297454 wieners to power the ISS FOR 2 1/2 days
Another mystery solved
All I can say is, as a guy who studies physics and appreciates this kind of breakdown.
Respect. Of the highest order.
o7
90 K * (24 hours * 60 minutes * 60 seconds) = 7,776,000 joules required in one day.
Isn't this correct?